Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
A | 3671 | 329 | 5 | 65.8000 |
O | 4154 | 319 | 7 | 45.5714 |
Os | 858 | 78 | 2 | 39.0000 |
Em | 845 | 78 | 2 | 39.0000 |
Para | 525 | 31 | 1 | 31.0000 |
No | 839 | 50 | 2 | 25.0000 |
Na | 594 | 48 | 2 | 24.0000 |
Mas | 327 | 18 | 1 | 18.0000 |
As | 583 | 36 | 2 | 18.0000 |
Ele | 420 | 32 | 2 | 16.0000 |
Ao | 226 | 15 | 1 | 15.0000 |
Eu | 238 | 27 | 2 | 13.5000 |
E | 472 | 27 | 2 | 13.5000 |
mas | 1163 | 49 | 4 | 12.2500 |
É | 482 | 24 | 2 | 12.0000 |
principalmente | 121 | 10 | 1 | 10.0000 |
num | 153 | 9 | 1 | 9.0000 |
Não | 388 | 27 | 3 | 9.0000 |
Nos | 95 | 9 | 1 | 9.0000 |
pra | 89 | 8 | 1 | 8.0000 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
tipo | 141 | 1 | 12 | 0.0833 |
R | 709 | 2 | 23 | 0.0870 |
disso | 318 | 1 | 10 | 0.1000 |
cerca | 259 | 1 | 9 | 0.1111 |
Estados | 157 | 1 | 8 | 0.1250 |
números | 68 | 1 | 8 | 0.1250 |
necessidade | 111 | 1 | 8 | 0.1250 |
próprio | 108 | 1 | 7 | 0.1429 |
redes | 229 | 1 | 7 | 0.1429 |
volume | 45 | 1 | 6 | 0.1667 |
artigo | 46 | 1 | 6 | 0.1667 |
recurso | 50 | 1 | 6 | 0.1667 |
Igreja | 54 | 1 | 6 | 0.1667 |
rua | 96 | 1 | 6 | 0.1667 |
povo | 55 | 1 | 6 | 0.1667 |
tribunal | 43 | 1 | 6 | 0.1667 |
quadro | 51 | 1 | 6 | 0.1667 |
limite | 50 | 1 | 6 | 0.1667 |
Brasileira | 66 | 1 | 6 | 0.1667 |
troca | 53 | 1 | 6 | 0.1667 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II